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ࡱ > a W0 Y0 / / / / / / / / / / 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 !0 "0 #0 $0 %0 &0 '0 (0 )0 *0 +0 ,0 -0 .0 /0 00 10 20 30 40 50 60 70 80 90 :0 ;0 <0 =0 >0 ?0 @0 A0 B0 C0 D0 E0 F0 G0 H0 I0 J0 K0 L0 M0 N0 O0 P0 Q0 R0 S0 T0 U0 V0 _ t bjbj,E,E O$ N/ N/ sl ! m $ @2 @2 @2 P' Y |n @2 v $ + 6d 8 v O d d d F < d d d RH @ d Z\ L d e 0 d m d m d m d ( d d m : UTME 2001 9. Questions - Type U y 1. Evaluate 21.05347 - 1.6324 x 0.43, to 3 decimal places. A. 20.980 B. 20.351 C. 20.981 D. 20.352 -1 1 2 . S i m p l i f y 3 6 4 a 3 P - 2 T x S -1 A. 4a B. 1 C. 8A D. 1 -2 8a 4a 3. Given that p = 1 + 2 and q = 1 - 2 , 2 2 Triangle PST is the solution of the linear evaluate p - q . i n e q u a l i t i e s 2 p q A . 2 y x 2 0 , y + 2 x + 2 0 , A . 2 ( 2 + 2 ) B . 2 ( 2 + 2 ) - 2 x - 1 C . 2 2 D . - 2 2 . B . 2 x 2 , y 0 , y + 2 x + 2 0 , x 0 4 . A c a r d e a l e r b o u g h t a s e c o n d - h a n d c a r f o r # 2 5 0 , 0 0 0 . 0 0 a n d s p e n t # 7 0 , 0 0 0 . 0 0 r e f u r b i s h i n g i t . H e t h e n s o l d t h e c a r f o r # 4 0 0 , 0 0 0 . 0 0 . W h a t i s t h e p e r c e n t a g e g a i n ? A . 6 0 % B . 3 2 % C . 2 5 % D . 2 0 % 1 0 . C . 2 y x 2 0 , y + 2 x + 2 0 , y 0 , x 0 D . 2 y x 2 0 , y + 2 x + 2 0 , x 0 . y x 3 1 1 x 2 5 . I f . 2 = x , e v a l u a t e + 3 2 - 2 y 2 A . 5 B . 5 8 2 y C . 5 D . 5 . 4 16 The identity element with respect to the multiplication shown in the table above is 6. Find the principal which amounts to #5,500 at simple interest in 5 years at 2% per annum. A. #4,900 B. #5,000 C. #4,700 D. #4,800 7. Evaluate (0 . 1 4 )2 0 . 2 7 5 , c o r r e c t t o 3 d e c i m a l 7 ( 0 . 0 2 ) p l a c e s . A . 0 . 0 3 9 B . 0 . 3 5 8 A . 0 B . m C . l D . k 1 1 . A m a n s a v e s # 1 0 0 . 0 0 i n h i s f i r s t y e a r o f w o r k a n d e a c h y e a r s a v e s # 2 0 . 0 0 m o r e t h a n i n t h e p r e c e d i n g y e a r . I n h o w m a n y y ears will he save #5,800.00? A. 100 years B. 58 years C. 29 years D. 20 years C. 0.033 D. 0.308. 8. Divide a3x - 26a2x + 156ax - 216 by a2x 24ax + 108. A. ax 2 B. ax + 2 C. ax 18 D. ax 6 3 1 2 . I f P = - 6 - 2 4 0 6 , t h e n , - 2 P i s 5 - 1 4 - 8 A . - 1 0 - 1 4 0 - 1 0 - 1 2 - 6 B . - 1 0 - 1 4 - 4 - 2 - 1 0 2 - 1 2 e l e m e n t i s 1 , f i n d t h e i n v e r s e o f t h e e l e m e n t 2 u n d e r * . A . 4 B . 0 C . 2 D . 4 - 6 4 C . - 1 0 0 - 1 4 5 - 6 4 - 8 6 - 1 - 8 1 9 . T h e s i x t h t e r m o f a n a r i t h m e t i c a l p r o g r e s s i o n i s h a l f o f i t s t w e l f t h t e r m . T h e f i r s t t e r m i s e q u a l t o A . z e r o D . 5 7 0 6 5 - 1 2 1 B . h a l f o f t h e c o m m o n d i f f e r e n c e C . d o u b l e t h e c o m m o n d i f f e r e n c e D . t h e c o m m o n d i f f e r e n c e . 1 3 . G i v e n t h e m a t r i x K = , t h e m a t r i x K 2 2 0 . F a c t o r i z e 4 x 2 9 y 2 + 2 0 x + 2 5 3 4 + K + I w h e r e I i s t h e 2 x 2 i d e n t i t y m a t r i x , i s A . ( 2 x 3 y + 5 ) ( 2 x 3 y 5 ) B . ( 2 x 3 y ) ( 2 x + 3 y ) 7 2 A . 6 3 B . C . ( 2 x 3 y + 5 ) ( 2 x + 3 y + 5 ) D . ( 2 x + 5 ) ( 2 x 9 y + 5 ) 1 2 9 2 1 8 1 3 1 0 2 0 7 2 1 . A s e c t o r o f a c i r c l e o f r a d i u s 7 . 2 c m w h i c h 0 C . D . s u b t e n d s a n a n g l e o f 3 0 0 a t t h e c e n t e r i s 2 2 2 3 2 1 2 4 u s e d t o f o r m a c o n e . W h a t i s t h e r a d i u s o f t h e b a s e o f t h e c o n e ? 1 4 . I f t w o g r a p h s y = p x 2 + q a n d y = 2 x 2 1 i n t e r s e c t a t x = 2 , f i n d t h e v a l u e o f p i n t e r m s o f q . A . 8 c m B . 6 c m C . 9 c m D . 7 c m . 2 2 . A p o i n t P m o v e s s u c h t h a t i t i s e q u i d i s t a n t f r o m p o i n t s Q a n d R . F i n d / Q R / w h e n / P R / 0 A . q - 8 B . 7 - q C . 8 - q D . 7 + q = 8 c m a n d <